Solve f(3)=8/13quad3+8

$$f ( 3 ) = \frac { 8 } { 13 } \quad 3 + 8$$

Evaluate

$$\frac{128}{13}\approx 9.846153846$$

Solution Steps

Express \frac{8}{13}\times 3 as a single fraction.

$$\frac{8\times 3}{13}+8$$

Multiply 8 and 3 to get 24.

$$\frac{24}{13}+8$$

Convert 8 to fraction \frac{104}{13}.

$$\frac{24}{13}+\frac{104}{13}$$

Since \frac{24}{13} and \frac{104}{13} have the same denominator, add them by adding their numerators.

$$\frac{24+104}{13}$$

Add 24 and 104 to get 128.

$$\frac{128}{13}$$

Factor

$$\frac{2 ^ {7}}{13} = 9\frac{11}{13} = 9.846153846153847$$