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1+3h+3h^{2}+h^{3}+3\left(1+b\right)
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(1+h\right)^{3}.
1+3h+3h^{2}+h^{3}+3+3b
Use the distributive property to multiply 3 by 1+b.
4+3h+3h^{2}+h^{3}+3b
Add 1 and 3 to get 4.
1+3h+3h^{2}+h^{3}+3\left(1+b\right)
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(1+h\right)^{3}.
1+3h+3h^{2}+h^{3}+3+3b
Use the distributive property to multiply 3 by 1+b.
4+3h+3h^{2}+h^{3}+3b
Add 1 and 3 to get 4.