Solve f(3-y/4)=3-4(3-y/4)

$$f ( \frac { 3 - y } { 4 } ) = 3 - 4 ( \frac { 3 - y } { 4 } )$$

Evaluate

$$y$$

Solution Steps

Cancel out 4 and 4.

$$3-\left(3-y\right)$$

To find the opposite of 3-y, find the opposite of each term.

$$3-3-\left(-y\right)$$

The opposite of -y is y.

$$3-3+y$$

Subtract 3 from 3 to get 0.

$$y$$

Differentiate w.r.t. y

$$1$$

Steps Using Definition of a Derivative

Cancel out 4 and 4.

$$\frac{\mathrm{d}}{\mathrm{d}y}(3-\left(3-y\right))$$

To find the opposite of 3-y, find the opposite of each term.

$$\frac{\mathrm{d}}{\mathrm{d}y}(3-3-\left(-y\right))$$

The opposite of -y is y.

$$\frac{\mathrm{d}}{\mathrm{d}y}(3-3+y)$$

Subtract 3 from 3 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y)$$

The derivative of ax^{n} is nax^{n-1}.

$$y^{1-1}$$

Subtract 1 from 1.

$$y^{0}$$

For any term t except 0, t^{0}=1.

$$1$$