Solve fx/2+4=x/3

$$f \frac { x } { 2 } + 4 = \frac { x } { 3 }$$

Solve for f

$$f=\frac{2}{3}-\frac{8}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 2,3.

$$3fx+24=2x$$

Subtract 24 from both sides.

$$3fx=2x-24$$

The equation is in standard form.

$$3xf=2x-24$$

Divide both sides by 3x.

$$\frac{3xf}{3x}=\frac{2x-24}{3x}$$

Dividing by 3x undoes the multiplication by 3x.

$$f=\frac{2x-24}{3x}$$

Divide -24+2x by 3x.

$$f=\frac{2}{3}-\frac{8}{x}$$

Solve for x

$$x=-\frac{24}{3f-2}$$

$$f\neq \frac{2}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 2,3.

$$3fx+24=2x$$

Subtract 2x from both sides.

$$3fx+24-2x=0$$

Subtract 24 from both sides. Anything subtracted from zero gives its negation.

$$3fx-2x=-24$$

Combine all terms containing x.

$$\left(3f-2\right)x=-24$$

Divide both sides by 3f-2.

$$\frac{\left(3f-2\right)x}{3f-2}=-\frac{24}{3f-2}$$

Dividing by 3f-2 undoes the multiplication by 3f-2.

$$x=-\frac{24}{3f-2}$$