Solve f:y=(1/2)-3

$$f : y = ( \frac { 1 } { 2 } ) - 3$$

Solve for f

$$f=-\frac{5y}{2}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2y, the least common multiple of y,2.

$$2f=2y\times \frac{1}{2}+2y\left(-3\right)$$

Multiply 2 and \frac{1}{2} to get 1.

$$2f=y+2y\left(-3\right)$$

Multiply 2 and -3 to get -6.

$$2f=y-6y$$

Combine y and -6y to get -5y.

$$2f=-5y$$

Divide both sides by 2.

$$\frac{2f}{2}=-\frac{5y}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$f=-\frac{5y}{2}$$

Solve for y

$$y=-\frac{2f}{5}$$

$$f\neq 0$$

Steps for Solving Linear Equation

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2y, the least common multiple of y,2.

$$2f=2y\times \frac{1}{2}+2y\left(-3\right)$$

Multiply 2 and \frac{1}{2} to get 1.

$$2f=y+2y\left(-3\right)$$

Multiply 2 and -3 to get -6.

$$2f=y-6y$$

Combine y and -6y to get -5y.

$$2f=-5y$$

Swap sides so that all variable terms are on the left hand side.

$$-5y=2f$$

Divide both sides by -5.

$$\frac{-5y}{-5}=\frac{2f}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$y=\frac{2f}{-5}$$

Divide 2f by -5.

$$y=-\frac{2f}{5}$$

Variable y cannot be equal to 0.

$$y=-\frac{2f}{5}\text{, }y\neq 0$$