Solve for y
y=\frac{С}{e^{3x}}+\frac{x}{3}-\frac{1}{9}
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e^{3x}y=\frac{xe^{3x}}{3}-\frac{e^{3x}}{9}+С
The equation is in standard form.
\frac{e^{3x}y}{e^{3x}}=\frac{\frac{xe^{3x}}{3}-\frac{e^{3x}}{9}+С}{e^{3x}}
Divide both sides by e^{3x}.
y=\frac{\frac{xe^{3x}}{3}-\frac{e^{3x}}{9}+С}{e^{3x}}
Dividing by e^{3x} undoes the multiplication by e^{3x}.
y=\frac{С}{e^{3x}}+\frac{x}{3}-\frac{1}{9}
Divide \frac{e^{3x}x}{3}-\frac{e^{3x}}{9}+С by e^{3x}.
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