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e^{2y}=4
Use the rules of exponents and logarithms to solve the equation.
\log(e^{2y})=\log(4)
Take the logarithm of both sides of the equation.
2y\log(e)=\log(4)
The logarithm of a number raised to a power is the power times the logarithm of the number.
2y=\frac{\log(4)}{\log(e)}
Divide both sides by \log(e).
2y=\log_{e}\left(4\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
y=\frac{2\ln(2)}{2}
Divide both sides by 2.