Solve e^2x-1-2=0

$$e ^ { 2 x - 1 } - 2 = 0$$

Solve for x

$$x=\frac{\ln(2)+1}{2}\approx 0.84657359$$

Steps Using Definition of Logarithm

Use the rules of exponents and logarithms to solve the equation.

$$e^{2x-1}-2=0$$

Add 2 to both sides of the equation.

$$e^{2x-1}=2$$

Take the logarithm of both sides of the equation.

$$\log(e^{2x-1})=\log(2)$$

The logarithm of a number raised to a power is the power times the logarithm of the number.

$$\left(2x-1\right)\log(e)=\log(2)$$

Divide both sides by \log(e).

$$2x-1=\frac{\log(2)}{\log(e)}$$

By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$2x-1=\log_{e}\left(2\right)$$

Add 1 to both sides of the equation.

$$2x=\ln(2)-\left(-1\right)$$

Divide both sides by 2.

$$x=\frac{\ln(2)+1}{2}$$

Solve for x (complex solution)

$$x=\frac{\ln(2)+1}{2}+i\pi n_{1}$$

$$n_{1}\in \mathrm{Z}$$