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e^{3t-5}=1
Use the rules of exponents and logarithms to solve the equation.
\log(e^{3t-5})=\log(1)
Take the logarithm of both sides of the equation.
\left(3t-5\right)\log(e)=\log(1)
The logarithm of a number raised to a power is the power times the logarithm of the number.
3t-5=\frac{\log(1)}{\log(e)}
Divide both sides by \log(e).
3t-5=\log_{e}\left(1\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
3t=-\left(-5\right)
Add 5 to both sides of the equation.
t=\frac{5}{3}
Divide both sides by 3.