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Solve for D
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e=\frac{1}{5}a+\frac{1}{5}D
Divide each term of a+D by 5 to get \frac{1}{5}a+\frac{1}{5}D.
\frac{1}{5}a+\frac{1}{5}D=e
Swap sides so that all variable terms are on the left hand side.
\frac{1}{5}D=e-\frac{1}{5}a
Subtract \frac{1}{5}a from both sides.
\frac{1}{5}D=-\frac{a}{5}+e
The equation is in standard form.
\frac{\frac{1}{5}D}{\frac{1}{5}}=\frac{-\frac{a}{5}+e}{\frac{1}{5}}
Multiply both sides by 5.
D=\frac{-\frac{a}{5}+e}{\frac{1}{5}}
Dividing by \frac{1}{5} undoes the multiplication by \frac{1}{5}.
D=5e-a
Divide e-\frac{a}{5} by \frac{1}{5} by multiplying e-\frac{a}{5} by the reciprocal of \frac{1}{5}.
e=\frac{1}{5}a+\frac{1}{5}D
Divide each term of a+D by 5 to get \frac{1}{5}a+\frac{1}{5}D.
\frac{1}{5}a+\frac{1}{5}D=e
Swap sides so that all variable terms are on the left hand side.
\frac{1}{5}a=e-\frac{1}{5}D
Subtract \frac{1}{5}D from both sides.
\frac{1}{5}a=-\frac{D}{5}+e
The equation is in standard form.
\frac{\frac{1}{5}a}{\frac{1}{5}}=\frac{-\frac{D}{5}+e}{\frac{1}{5}}
Multiply both sides by 5.
a=\frac{-\frac{D}{5}+e}{\frac{1}{5}}
Dividing by \frac{1}{5} undoes the multiplication by \frac{1}{5}.
a=5e-D
Divide e-\frac{D}{5} by \frac{1}{5} by multiplying e-\frac{D}{5} by the reciprocal of \frac{1}{5}.