d y = 2 - 3 x + x ^ { 3 }
Solve for d
\left\{\begin{matrix}d=\frac{\left(x+2\right)\left(x-1\right)^{2}}{y}\text{, }&y\neq 0\\d\in \mathrm{R}\text{, }&\left(x=-2\text{ or }x=1\right)\text{ and }y=0\end{matrix}\right.
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yd=x^{3}-3x+2
The equation is in standard form.
\frac{yd}{y}=\frac{\left(x+2\right)\left(x-1\right)^{2}}{y}
Divide both sides by y.
d=\frac{\left(x+2\right)\left(x-1\right)^{2}}{y}
Dividing by y undoes the multiplication by y.
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