d x = \sqrt { 5 x + 2 }
Solve for d
d=\frac{\sqrt{5x+2}}{x}
x\neq 0\text{ and }x\geq -\frac{2}{5}
Solve for x
\left\{\begin{matrix}x=\frac{\sqrt{8d^{2}+25}+5}{2d^{2}}\text{, }&d>0\\x=-\frac{\sqrt{8d^{2}+25}-5}{2d^{2}}\text{, }&d<0\\x=-\frac{2}{5}\text{, }&d=0\end{matrix}\right.
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xd=\sqrt{5x+2}
The equation is in standard form.
\frac{xd}{x}=\frac{\sqrt{5x+2}}{x}
Divide both sides by x.
d=\frac{\sqrt{5x+2}}{x}
Dividing by x undoes the multiplication by x.
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