d x = \int \frac { 1 } { 1 - x ^ { 2 } } d x
Solve for d
\left\{\begin{matrix}d=\frac{С}{x}-\frac{\ln(\frac{|x-1|}{|x+1|})}{2x}\text{, }&x\neq 0\text{ and }|x|\neq 1\\d\in \mathrm{R}\text{, }&x=0\text{ and }С=0\end{matrix}\right.
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xd=-\frac{\ln(\frac{|x-1|}{|x+1|})}{2}+С
The equation is in standard form.
\frac{xd}{x}=\frac{-\frac{\ln(\frac{|x-1|}{|x+1|})}{2}+С}{x}
Divide both sides by x.
d=\frac{-\frac{\ln(\frac{|x-1|}{|x+1|})}{2}+С}{x}
Dividing by x undoes the multiplication by x.
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