d x + 3 = 1
Solve for d
d=-\frac{2}{x}
x\neq 0
Solve for x
x=-\frac{2}{d}
d\neq 0
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dx=1-3
Subtract 3 from both sides.
dx=-2
Subtract 3 from 1 to get -2.
xd=-2
The equation is in standard form.
\frac{xd}{x}=-\frac{2}{x}
Divide both sides by x.
d=-\frac{2}{x}
Dividing by x undoes the multiplication by x.
dx=1-3
Subtract 3 from both sides.
dx=-2
Subtract 3 from 1 to get -2.
\frac{dx}{d}=-\frac{2}{d}
Divide both sides by d.
x=-\frac{2}{d}
Dividing by d undoes the multiplication by d.
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