Solve d21:(5^2-3^2*2)+(5*1-2*2)^5+1

$$d 21 : ( 5 ^ { 2 } - 3 ^ { 2 } \cdot 2 ) + ( 5 \cdot 1 - 2 \times 2 ) ^ { 5 } + 1$$

Evaluate

$$\frac{d_{21}}{7}+2$$

Short Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\frac{d_{21}}{25-3^{2}\times 2}+\left(5\times 1-2\times 2\right)^{5}+1$$

Calculate 3 to the power of 2 and get 9.

$$\frac{d_{21}}{25-9\times 2}+\left(5\times 1-2\times 2\right)^{5}+1$$

Multiply 9 and 2 to get 18.

$$\frac{d_{21}}{25-18}+\left(5\times 1-2\times 2\right)^{5}+1$$

Subtract 18 from 25 to get 7.

$$\frac{d_{21}}{7}+\left(5\times 1-2\times 2\right)^{5}+1$$

Multiply 5 and 1 to get 5.

$$\frac{d_{21}}{7}+\left(5-2\times 2\right)^{5}+1$$

Multiply 2 and 2 to get 4.

$$\frac{d_{21}}{7}+\left(5-4\right)^{5}+1$$

Subtract 4 from 5 to get 1.

$$\frac{d_{21}}{7}+1^{5}+1$$

Calculate 1 to the power of 5 and get 1.

$$\frac{d_{21}}{7}+1+1$$

Add 1 and 1 to get 2.

$$\frac{d_{21}}{7}+2$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 2 times \frac{7}{7}.

$$\frac{d_{21}}{7}+\frac{2\times 7}{7}$$

Since \frac{d_{21}}{7} and \frac{2\times 7}{7} have the same denominator, add them by adding their numerators.

$$\frac{d_{21}+2\times 7}{7}$$

Do the multiplications in d_{21}+2\times 7.

$$\frac{d_{21}+14}{7}$$

Expand

$$\frac{d_{21}}{7}+2$$

Short Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\frac{d_{21}}{25-3^{2}\times 2}+\left(5\times 1-2\times 2\right)^{5}+1$$

Calculate 3 to the power of 2 and get 9.

$$\frac{d_{21}}{25-9\times 2}+\left(5\times 1-2\times 2\right)^{5}+1$$

Multiply 9 and 2 to get 18.

$$\frac{d_{21}}{25-18}+\left(5\times 1-2\times 2\right)^{5}+1$$

Subtract 18 from 25 to get 7.

$$\frac{d_{21}}{7}+\left(5\times 1-2\times 2\right)^{5}+1$$

Multiply 5 and 1 to get 5.

$$\frac{d_{21}}{7}+\left(5-2\times 2\right)^{5}+1$$

Multiply 2 and 2 to get 4.

$$\frac{d_{21}}{7}+\left(5-4\right)^{5}+1$$

Subtract 4 from 5 to get 1.

$$\frac{d_{21}}{7}+1^{5}+1$$

Calculate 1 to the power of 5 and get 1.

$$\frac{d_{21}}{7}+1+1$$

Add 1 and 1 to get 2.

$$\frac{d_{21}}{7}+2$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 2 times \frac{7}{7}.

$$\frac{d_{21}}{7}+\frac{2\times 7}{7}$$

Since \frac{d_{21}}{7} and \frac{2\times 7}{7} have the same denominator, add them by adding their numerators.

$$\frac{d_{21}+2\times 7}{7}$$

Do the multiplications in d_{21}+2\times 7.

$$\frac{d_{21}+14}{7}$$