Solve d^2>d

$$d ^ { 2 } > d$$

Solve for d

$$d\in \left(-\infty,0\right)\cup \left(1,\infty\right)$$

Solution Steps

Subtract d from both sides.

$$d^{2}-d>0$$

Factor out d.

$$d\left(d-1\right)>0$$

For the product to be positive, d and d-1 have to be both negative or both positive. Consider the case when d and d-1 are both negative.

$$d<0 d-1<0$$

The solution satisfying both inequalities is d<0.

$$d<0$$

Consider the case when d and d-1 are both positive.

$$d-1>0 d>0$$

The solution satisfying both inequalities is d>1.

$$d>1$$

The final solution is the union of the obtained solutions.

$$d<0\text{; }d>1$$