Solve d=-002d^2+2d

$$d = - 002 d ^ { 2 } + 2 d$$

Solve for d

$$d=0$$

Steps for Solving Linear Equation

Multiply 0 and 0 to get 0.

$$d=0\times 2d^{2}+2d$$

Multiply 0 and 2 to get 0.

$$d=0d^{2}+2d$$

Anything times zero gives zero.

$$d=0+2d$$

Anything plus zero gives itself.

$$d=2d$$

Subtract 2d from both sides.

$$d-2d=0$$

Combine d and -2d to get -d.

$$-d=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -1 is not equal to 0, d must be equal to 0.

$$d=0$$