Solve d=sqrt{14^2+-7^2}

$$d = \sqrt { 14 ^ { 2 } + - 7 ^ { 2 } }$$

Solve for d

$$d=7\sqrt{3}\approx 12.124355653$$

Steps for Solving Linear Equation

Calculate 14 to the power of 2 and get 196.

$$d=\sqrt{196-7^{2}}$$

Calculate 7 to the power of 2 and get 49.

$$d=\sqrt{196-49}$$

Subtract 49 from 196 to get 147.

$$d=\sqrt{147}$$

Factor 147=7^{2}\times 3. Rewrite the square root of the product \sqrt{7^{2}\times 3} as the product of square roots \sqrt{7^{2}}\sqrt{3}. Take the square root of 7^{2}.

$$d=7\sqrt{3}$$

Assign d

$$d≔7\sqrt{3}$$