Solve for c (complex solution)
\left\{\begin{matrix}c=\frac{x\left(2x+5\right)}{t}\text{, }&t\neq 0\\c\in \mathrm{C}\text{, }&\left(x=0\text{ or }x=-\frac{5}{2}\right)\text{ and }t=0\end{matrix}\right.
Solve for t (complex solution)
\left\{\begin{matrix}t=\frac{x\left(2x+5\right)}{c}\text{, }&c\neq 0\\t\in \mathrm{C}\text{, }&\left(x=0\text{ or }x=-\frac{5}{2}\right)\text{ and }c=0\end{matrix}\right.
Solve for c
\left\{\begin{matrix}c=\frac{x\left(2x+5\right)}{t}\text{, }&t\neq 0\\c\in \mathrm{R}\text{, }&\left(x=0\text{ or }x=-\frac{5}{2}\right)\text{ and }t=0\end{matrix}\right.
Solve for t
\left\{\begin{matrix}t=\frac{x\left(2x+5\right)}{c}\text{, }&c\neq 0\\t\in \mathrm{R}\text{, }&\left(x=0\text{ or }x=-\frac{5}{2}\right)\text{ and }c=0\end{matrix}\right.
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ct-5x=2x^{2}
Add 2x^{2} to both sides. Anything plus zero gives itself.
ct=2x^{2}+5x
Add 5x to both sides.
tc=2x^{2}+5x
The equation is in standard form.
\frac{tc}{t}=\frac{x\left(2x+5\right)}{t}
Divide both sides by t.
c=\frac{x\left(2x+5\right)}{t}
Dividing by t undoes the multiplication by t.
ct-5x=2x^{2}
Add 2x^{2} to both sides. Anything plus zero gives itself.
ct=2x^{2}+5x
Add 5x to both sides.
\frac{ct}{c}=\frac{x\left(2x+5\right)}{c}
Divide both sides by c.
t=\frac{x\left(2x+5\right)}{c}
Dividing by c undoes the multiplication by c.
ct-5x=2x^{2}
Add 2x^{2} to both sides. Anything plus zero gives itself.
ct=2x^{2}+5x
Add 5x to both sides.
tc=2x^{2}+5x
The equation is in standard form.
\frac{tc}{t}=\frac{x\left(2x+5\right)}{t}
Divide both sides by t.
c=\frac{x\left(2x+5\right)}{t}
Dividing by t undoes the multiplication by t.
ct-5x=2x^{2}
Add 2x^{2} to both sides. Anything plus zero gives itself.
ct=2x^{2}+5x
Add 5x to both sides.
\frac{ct}{c}=\frac{x\left(2x+5\right)}{c}
Divide both sides by c.
t=\frac{x\left(2x+5\right)}{c}
Dividing by c undoes the multiplication by c.
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Limits
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