Solve for c
c=-\frac{40}{x}
x\neq 0
Solve for x
x=-\frac{40}{c}
c\neq 0
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c\times 0.3x=-7-5
Subtract 5 from both sides.
c\times 0.3x=-12
Subtract 5 from -7 to get -12.
\frac{3x}{10}c=-12
The equation is in standard form.
\frac{10\times \frac{3x}{10}c}{3x}=\frac{-12\times 10}{3x}
Divide both sides by 0.3x.
c=\frac{-12\times 10}{3x}
Dividing by 0.3x undoes the multiplication by 0.3x.
c=-\frac{40}{x}
Divide -12 by 0.3x.
c\times 0.3x=-7-5
Subtract 5 from both sides.
c\times 0.3x=-12
Subtract 5 from -7 to get -12.
\frac{3c}{10}x=-12
The equation is in standard form.
\frac{10\times \frac{3c}{10}x}{3c}=\frac{-12\times 10}{3c}
Divide both sides by 0.3c.
x=\frac{-12\times 10}{3c}
Dividing by 0.3c undoes the multiplication by 0.3c.
x=-\frac{40}{c}
Divide -12 by 0.3c.
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