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c^{2}-c+2=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
c=\frac{-\left(-1\right)±\sqrt{1-4\times 2}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and 2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
c=\frac{-\left(-1\right)±\sqrt{1-8}}{2}
Multiply -4 times 2.
c=\frac{-\left(-1\right)±\sqrt{-7}}{2}
Add 1 to -8.
c=\frac{-\left(-1\right)±\sqrt{7}i}{2}
Take the square root of -7.
c=\frac{1±\sqrt{7}i}{2}
The opposite of -1 is 1.
c=\frac{1+\sqrt{7}i}{2}
Now solve the equation c=\frac{1±\sqrt{7}i}{2} when ± is plus. Add 1 to i\sqrt{7}.
c=\frac{-\sqrt{7}i+1}{2}
Now solve the equation c=\frac{1±\sqrt{7}i}{2} when ± is minus. Subtract i\sqrt{7} from 1.
c=\frac{1+\sqrt{7}i}{2} c=\frac{-\sqrt{7}i+1}{2}
The equation is now solved.
c^{2}-c+2=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
c^{2}-c+2-2=-2
Subtract 2 from both sides of the equation.
c^{2}-c=-2
Subtracting 2 from itself leaves 0.
c^{2}-c+\left(-\frac{1}{2}\right)^{2}=-2+\left(-\frac{1}{2}\right)^{2}
Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
c^{2}-c+\frac{1}{4}=-2+\frac{1}{4}
Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.
c^{2}-c+\frac{1}{4}=-\frac{7}{4}
Add -2 to \frac{1}{4}.
\left(c-\frac{1}{2}\right)^{2}=-\frac{7}{4}
Factor c^{2}-c+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(c-\frac{1}{2}\right)^{2}}=\sqrt{-\frac{7}{4}}
Take the square root of both sides of the equation.
c-\frac{1}{2}=\frac{\sqrt{7}i}{2} c-\frac{1}{2}=-\frac{\sqrt{7}i}{2}
Simplify.
c=\frac{1+\sqrt{7}i}{2} c=\frac{-\sqrt{7}i+1}{2}
Add \frac{1}{2} to both sides of the equation.
x ^ 2 -1x +2 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 1 rs = 2
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{1}{2} - u s = \frac{1}{2} + u
Two numbers r and s sum up to 1 exactly when the average of the two numbers is \frac{1}{2}*1 = \frac{1}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{1}{2} - u) (\frac{1}{2} + u) = 2
To solve for unknown quantity u, substitute these in the product equation rs = 2
\frac{1}{4} - u^2 = 2
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 2-\frac{1}{4} = \frac{7}{4}
Simplify the expression by subtracting \frac{1}{4} on both sides
u^2 = -\frac{7}{4} u = \pm\sqrt{-\frac{7}{4}} = \pm \frac{\sqrt{7}}{2}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{1}{2} - \frac{\sqrt{7}}{2}i = 0.500 - 1.323i s = \frac{1}{2} + \frac{\sqrt{7}}{2}i = 0.500 + 1.323i
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.