Solve for b
\left\{\begin{matrix}b=\frac{a+3}{t}\text{, }&t\neq 0\\b\in \mathrm{R}\text{, }&a=-3\text{ and }t=0\end{matrix}\right.
Solve for a
a=bt-3
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bt=a+3
Add 3 to both sides.
tb=a+3
The equation is in standard form.
\frac{tb}{t}=\frac{a+3}{t}
Divide both sides by t.
b=\frac{a+3}{t}
Dividing by t undoes the multiplication by t.
a=bt-3
Swap sides so that all variable terms are on the left hand side.
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