Solve for b
b=\frac{\left(\frac{3}{2}\right)^{n}+1}{n}
n\neq 0
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nb=\left(\frac{3}{2}\right)^{n}+1
The equation is in standard form.
\frac{nb}{n}=\frac{\left(\frac{3}{2}\right)^{n}+1}{n}
Divide both sides by n.
b=\frac{\left(\frac{3}{2}\right)^{n}+1}{n}
Dividing by n undoes the multiplication by n.
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