Solve b-2c=-2ax

$$b - 2 c = - 2 a x$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=\frac{2c-b}{2x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&b=2c\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-2ax=b-2c$$

The equation is in standard form.

$$\left(-2x\right)a=b-2c$$

Divide both sides by -2x.

$$\frac{\left(-2x\right)a}{-2x}=\frac{b-2c}{-2x}$$

Dividing by -2x undoes the multiplication by -2x.

$$a=\frac{b-2c}{-2x}$$

Divide b-2c by -2x.

$$a=-\frac{b-2c}{2x}$$

Solve for a

$$\left\{\begin{matrix}a=\frac{2c-b}{2x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=2c\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-2ax=b-2c$$

The equation is in standard form.

$$\left(-2x\right)a=b-2c$$

Divide both sides by -2x.

$$\frac{\left(-2x\right)a}{-2x}=\frac{b-2c}{-2x}$$

Dividing by -2x undoes the multiplication by -2x.

$$a=\frac{b-2c}{-2x}$$

Divide b-2c by -2x.

$$a=-\frac{b-2c}{2x}$$

Solve for b

$$b=2\left(c-ax\right)$$

Solution Steps

Add 2c to both sides.

$$b=-2ax+2c$$