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b\left(b-12\right)=0
Factor out b.
b=0 b=12
To find equation solutions, solve b=0 and b-12=0.
b^{2}-12b=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
b=\frac{-\left(-12\right)±\sqrt{\left(-12\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -12 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
b=\frac{-\left(-12\right)±12}{2}
Take the square root of \left(-12\right)^{2}.
b=\frac{12±12}{2}
The opposite of -12 is 12.
b=\frac{24}{2}
Now solve the equation b=\frac{12±12}{2} when ± is plus. Add 12 to 12.
b=12
Divide 24 by 2.
b=\frac{0}{2}
Now solve the equation b=\frac{12±12}{2} when ± is minus. Subtract 12 from 12.
b=0
Divide 0 by 2.
b=12 b=0
The equation is now solved.
b^{2}-12b=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
b^{2}-12b+\left(-6\right)^{2}=\left(-6\right)^{2}
Divide -12, the coefficient of the x term, by 2 to get -6. Then add the square of -6 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
b^{2}-12b+36=36
Square -6.
\left(b-6\right)^{2}=36
Factor b^{2}-12b+36. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(b-6\right)^{2}}=\sqrt{36}
Take the square root of both sides of the equation.
b-6=6 b-6=-6
Simplify.
b=12 b=0
Add 6 to both sides of the equation.