Solve b^2=(3x+1)+(-1*2)+(-2x-1)=

$$b ^ { 2 } = ( 3 x + 1 ) + ( - 1 \times 2 ) + ( - 2 x - 1 ) =$$

Solve for x

$$x=b^{2}+2$$

Solution Steps

Multiply -1 and 2 to get -2.

$$b^{2}=3x+1-2-2x-1$$

Subtract 2 from 1 to get -1.

$$b^{2}=3x-1-2x-1$$

Combine 3x and -2x to get x.

$$b^{2}=x-1-1$$

Subtract 1 from -1 to get -2.

$$b^{2}=x-2$$

Swap sides so that all variable terms are on the left hand side.

$$x-2=b^{2}$$

Add 2 to both sides.

$$x=b^{2}+2$$

Solve for b (complex solution)

$$b=-\sqrt{x-2}$$

$$b=\sqrt{x-2}$$

Solve for b

$$b=\sqrt{x-2}$$

$$b=-\sqrt{x-2}\text{, }x\geq 2$$