Solve b^2+2bc+c^2+4b^2+2bc+b^2

$$b ^ { 2 } + 2 b c + c ^ { 2 } + 4 b ^ { 2 } + 2 b c + b ^ { 2 }$$

Evaluate

$$6b^{2}+4bc+c^{2}$$

Solution Steps

Combine b^{2} and 4b^{2} to get 5b^{2}.

$$5b^{2}+2bc+c^{2}+2bc+b^{2}$$

Combine 2bc and 2bc to get 4bc.

$$5b^{2}+4bc+c^{2}+b^{2}$$

Combine 5b^{2} and b^{2} to get 6b^{2}.

$$6b^{2}+4bc+c^{2}$$

Differentiate w.r.t. b

$$4\left(3b+c\right)$$