Solve for b
b=-\frac{c}{1-c}
c\neq 1
Solve for c
c=-\frac{b}{1-b}
b\neq 1
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b+c-bc=0
Subtract bc from both sides.
b-bc=-c
Subtract c from both sides. Anything subtracted from zero gives its negation.
\left(1-c\right)b=-c
Combine all terms containing b.
\frac{\left(1-c\right)b}{1-c}=-\frac{c}{1-c}
Divide both sides by 1-c.
b=-\frac{c}{1-c}
Dividing by 1-c undoes the multiplication by 1-c.
b+c-bc=0
Subtract bc from both sides.
c-bc=-b
Subtract b from both sides. Anything subtracted from zero gives its negation.
\left(1-b\right)c=-b
Combine all terms containing c.
\frac{\left(1-b\right)c}{1-b}=-\frac{b}{1-b}
Divide both sides by 1-b.
c=-\frac{b}{1-b}
Dividing by 1-b undoes the multiplication by 1-b.
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