Solve for a
a=-\frac{3b+4}{b+3}
b\neq -3
Solve for b
b=-\frac{3a+4}{a+3}
a\neq -3
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ab+3a+4=-3b
Subtract 3b from both sides. Anything subtracted from zero gives its negation.
ab+3a=-3b-4
Subtract 4 from both sides.
\left(b+3\right)a=-3b-4
Combine all terms containing a.
\frac{\left(b+3\right)a}{b+3}=\frac{-3b-4}{b+3}
Divide both sides by b+3.
a=\frac{-3b-4}{b+3}
Dividing by b+3 undoes the multiplication by b+3.
a=-\frac{3b+4}{b+3}
Divide -3b-4 by b+3.
ab+3b+4=-3a
Subtract 3a from both sides. Anything subtracted from zero gives its negation.
ab+3b=-3a-4
Subtract 4 from both sides.
\left(a+3\right)b=-3a-4
Combine all terms containing b.
\frac{\left(a+3\right)b}{a+3}=\frac{-3a-4}{a+3}
Divide both sides by a+3.
b=\frac{-3a-4}{a+3}
Dividing by a+3 undoes the multiplication by a+3.
b=-\frac{3a+4}{a+3}
Divide -3a-4 by a+3.
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Limits
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