Solve for a (complex solution)
\left\{\begin{matrix}a=\frac{c+2b}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&b=-\frac{c}{2}\text{ and }x=0\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=\frac{c+2b}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=-\frac{c}{2}\text{ and }x=0\end{matrix}\right.
Solve for b
b=\frac{ax-c}{2}
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ax=c+2b
Add 2b to both sides.
xa=2b+c
The equation is in standard form.
\frac{xa}{x}=\frac{2b+c}{x}
Divide both sides by x.
a=\frac{2b+c}{x}
Dividing by x undoes the multiplication by x.
a=\frac{c+2b}{x}
Divide c+2b by x.
ax=c+2b
Add 2b to both sides.
xa=2b+c
The equation is in standard form.
\frac{xa}{x}=\frac{2b+c}{x}
Divide both sides by x.
a=\frac{2b+c}{x}
Dividing by x undoes the multiplication by x.
a=\frac{c+2b}{x}
Divide c+2b by x.
-2b=c-ax
Subtract ax from both sides.
\frac{-2b}{-2}=\frac{c-ax}{-2}
Divide both sides by -2.
b=\frac{c-ax}{-2}
Dividing by -2 undoes the multiplication by -2.
b=\frac{ax-c}{2}
Divide c-ax by -2.
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