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Solve for a
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ax^{3}+cx+d=-bx
Subtract bx from both sides. Anything subtracted from zero gives its negation.
ax^{3}+d=-bx-cx
Subtract cx from both sides.
ax^{3}=-bx-cx-d
Subtract d from both sides.
x^{3}a=-bx-cx-d
The equation is in standard form.
\frac{x^{3}a}{x^{3}}=\frac{-bx-cx-d}{x^{3}}
Divide both sides by x^{3}.
a=\frac{-bx-cx-d}{x^{3}}
Dividing by x^{3} undoes the multiplication by x^{3}.
a=-\frac{bx+cx+d}{x^{3}}
Divide -bx-cx-d by x^{3}.
bx+cx+d=-ax^{3}
Subtract ax^{3} from both sides. Anything subtracted from zero gives its negation.
bx+d=-ax^{3}-cx
Subtract cx from both sides.
bx=-ax^{3}-cx-d
Subtract d from both sides.
xb=-ax^{3}-cx-d
The equation is in standard form.
\frac{xb}{x}=\frac{-ax^{3}-cx-d}{x}
Divide both sides by x.
b=\frac{-ax^{3}-cx-d}{x}
Dividing by x undoes the multiplication by x.
b=-ax^{2}-c-\frac{d}{x}
Divide -ax^{3}-cx-d by x.