Solve ax^2+bx+35=0

$$a x ^ { 2 } + b x + 35 = 0$$

Solve for a

$$a=-\frac{bx+35}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract bx from both sides. Anything subtracted from zero gives its negation.

$$ax^{2}+35=-bx$$

Subtract 35 from both sides.

$$ax^{2}=-bx-35$$

The equation is in standard form.

$$x^{2}a=-bx-35$$

Divide both sides by x^{2}.

$$\frac{x^{2}a}{x^{2}}=\frac{-bx-35}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$a=\frac{-bx-35}{x^{2}}$$

Divide -bx-35 by x^{2}.

$$a=-\frac{bx+35}{x^{2}}$$

Solve for b

$$b=-ax-\frac{35}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract ax^{2} from both sides. Anything subtracted from zero gives its negation.

$$bx+35=-ax^{2}$$

Subtract 35 from both sides.

$$bx=-ax^{2}-35$$

The equation is in standard form.

$$xb=-ax^{2}-35$$

Divide both sides by x.

$$\frac{xb}{x}=\frac{-ax^{2}-35}{x}$$

Dividing by x undoes the multiplication by x.

$$b=\frac{-ax^{2}-35}{x}$$

Divide -ax^{2}-35 by x.

$$b=-ax-\frac{35}{x}$$