Solve ax^2+5=3

$$a x ^ { 2 } + 5 = 3$$

Solve for a

$$a=-\frac{2}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 5 from both sides.

$$ax^{2}=3-5$$

Subtract 5 from 3 to get -2.

$$ax^{2}=-2$$

The equation is in standard form.

$$x^{2}a=-2$$

Divide both sides by x^{2}.

$$\frac{x^{2}a}{x^{2}}=-\frac{2}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$a=-\frac{2}{x^{2}}$$

Solve for x

$$x=\sqrt{-\frac{2}{a}}$$

$$x=-\sqrt{-\frac{2}{a}}\text{, }a<0$$