Solve for a
a=4-\frac{8}{x}
x\neq 0
Solve for x
x=-\frac{8}{a-4}
a\neq 4
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ax=4x-3-5
Subtract 5 from both sides.
ax=4x-8
Subtract 5 from -3 to get -8.
xa=4x-8
The equation is in standard form.
\frac{xa}{x}=\frac{4x-8}{x}
Divide both sides by x.
a=\frac{4x-8}{x}
Dividing by x undoes the multiplication by x.
a=4-\frac{8}{x}
Divide -8+4x by x.
ax+5-4x=-3
Subtract 4x from both sides.
ax-4x=-3-5
Subtract 5 from both sides.
ax-4x=-8
Subtract 5 from -3 to get -8.
\left(a-4\right)x=-8
Combine all terms containing x.
\frac{\left(a-4\right)x}{a-4}=-\frac{8}{a-4}
Divide both sides by a-4.
x=-\frac{8}{a-4}
Dividing by a-4 undoes the multiplication by a-4.
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