Solve ax+3y-1=0

$$a x + 3 y - 1 = 0$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=\frac{1-3y}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&y=\frac{1}{3}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$ax-1=-3y$$

Add 1 to both sides.

$$ax=-3y+1$$

The equation is in standard form.

$$xa=1-3y$$

Divide both sides by x.

$$\frac{xa}{x}=\frac{1-3y}{x}$$

Dividing by x undoes the multiplication by x.

$$a=\frac{1-3y}{x}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=\frac{1-3y}{a}\text{, }&a\neq 0\\x\in \mathrm{C}\text{, }&y=\frac{1}{3}\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$ax-1=-3y$$

Add 1 to both sides.

$$ax=-3y+1$$

The equation is in standard form.

$$ax=1-3y$$

Divide both sides by a.

$$\frac{ax}{a}=\frac{1-3y}{a}$$

Dividing by a undoes the multiplication by a.

$$x=\frac{1-3y}{a}$$

Solve for a

$$\left\{\begin{matrix}a=\frac{1-3y}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&y=\frac{1}{3}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$ax-1=-3y$$

Add 1 to both sides.

$$ax=-3y+1$$

The equation is in standard form.

$$xa=1-3y$$

Divide both sides by x.

$$\frac{xa}{x}=\frac{1-3y}{x}$$

Dividing by x undoes the multiplication by x.

$$a=\frac{1-3y}{x}$$

Solve for x

$$\left\{\begin{matrix}x=\frac{1-3y}{a}\text{, }&a\neq 0\\x\in \mathrm{R}\text{, }&y=\frac{1}{3}\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$ax-1=-3y$$

Add 1 to both sides.

$$ax=-3y+1$$

The equation is in standard form.

$$ax=1-3y$$

Divide both sides by a.

$$\frac{ax}{a}=\frac{1-3y}{a}$$

Dividing by a undoes the multiplication by a.

$$x=\frac{1-3y}{a}$$