Solve ax+2y=-2quad(-1,2)

$$a x + 2 y = - 2 \quad ( - 1,2 )$$

Solve for a

$$\left\{\begin{matrix}a=-\frac{2y-2,4}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&y=\frac{6}{5}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply -2 and -1,2 to get 2,4.

$$ax+2y=2,4$$

Subtract 2y from both sides.

$$ax=2,4-2y$$

The equation is in standard form.

$$xa=2,4-2y$$

Divide both sides by x.

$$\frac{xa}{x}=\frac{2,4-2y}{x}$$

Dividing by x undoes the multiplication by x.

$$a=\frac{2,4-2y}{x}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{2y-2,4}{a}\text{, }&a\neq 0\\x\in \mathrm{R}\text{, }&y=\frac{6}{5}\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply -2 and -1,2 to get 2,4.

$$ax+2y=2,4$$

Subtract 2y from both sides.

$$ax=2,4-2y$$

Divide both sides by a.

$$\frac{ax}{a}=\frac{2,4-2y}{a}$$

Dividing by a undoes the multiplication by a.

$$x=\frac{2,4-2y}{a}$$