Solve for a (complex solution)
\left\{\begin{matrix}a=-\frac{1-2c}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&c=\frac{1}{2}\text{ and }x=0\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=-\frac{1-2c}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&c=\frac{1}{2}\text{ and }x=0\end{matrix}\right.
Solve for c
c=\frac{ax+1}{2}
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ax=2c-1
Subtract 1 from both sides.
xa=2c-1
The equation is in standard form.
\frac{xa}{x}=\frac{2c-1}{x}
Divide both sides by x.
a=\frac{2c-1}{x}
Dividing by x undoes the multiplication by x.
ax=2c-1
Subtract 1 from both sides.
xa=2c-1
The equation is in standard form.
\frac{xa}{x}=\frac{2c-1}{x}
Divide both sides by x.
a=\frac{2c-1}{x}
Dividing by x undoes the multiplication by x.
2c=ax+1
Swap sides so that all variable terms are on the left hand side.
\frac{2c}{2}=\frac{ax+1}{2}
Divide both sides by 2.
c=\frac{ax+1}{2}
Dividing by 2 undoes the multiplication by 2.
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Simultaneous equation
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Limits
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