Solve aab=1(1-6)+(2-5)

$$a a b = 1 ( 1 - 6 ) + ( 2 - 5 )$$

Solve for b

$$b=-\frac{8}{a^{2}}$$

$$a\neq 0$$

Steps for Solving Linear Equation

Multiply a and a to get a^{2}.

$$a^{2}b=1\left(1-6\right)+2-5$$

Subtract 6 from 1 to get -5.

$$a^{2}b=1\left(-5\right)+2-5$$

Multiply 1 and -5 to get -5.

$$a^{2}b=-5+2-5$$

Add -5 and 2 to get -3.

$$a^{2}b=-3-5$$

Subtract 5 from -3 to get -8.

$$a^{2}b=-8$$

Divide both sides by a^{2}.

$$\frac{a^{2}b}{a^{2}}=-\frac{8}{a^{2}}$$

Dividing by a^{2} undoes the multiplication by a^{2}.

$$b=-\frac{8}{a^{2}}$$

Solve for a (complex solution)

$$a=-2\sqrt{2}ib^{-\frac{1}{2}}$$

$$a=2\sqrt{2}ib^{-\frac{1}{2}}\text{, }b\neq 0$$

Solve for a

$$a=2\sqrt{-\frac{2}{b}}$$

$$a=-2\sqrt{-\frac{2}{b}}\text{, }b<0$$