Solve aquad2y-x=7

$$a \quad 2 y - x = 7$$

Solve for a_2 (complex solution)

$$\left\{\begin{matrix}a_{2}=\frac{x+7}{y}\text{, }&y\neq 0\\a_{2}\in \mathrm{C}\text{, }&x=-7\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Add x to both sides.

$$a_{2}y=7+x$$

The equation is in standard form.

$$ya_{2}=x+7$$

Divide both sides by y.

$$\frac{ya_{2}}{y}=\frac{x+7}{y}$$

Dividing by y undoes the multiplication by y.

$$a_{2}=\frac{x+7}{y}$$

Solve for a_2

$$\left\{\begin{matrix}a_{2}=\frac{x+7}{y}\text{, }&y\neq 0\\a_{2}\in \mathrm{R}\text{, }&x=-7\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Add x to both sides.

$$a_{2}y=7+x$$

The equation is in standard form.

$$ya_{2}=x+7$$

Divide both sides by y.

$$\frac{ya_{2}}{y}=\frac{x+7}{y}$$

Dividing by y undoes the multiplication by y.

$$a_{2}=\frac{x+7}{y}$$

Solve for x

$$x=a_{2}y-7$$

Steps for Solving Linear Equation

Subtract a_{2}y from both sides.

$$-x=7-a_{2}y$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{7-a_{2}y}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{7-a_{2}y}{-1}$$

Divide 7-a_{2}y by -1.

$$x=a_{2}y-7$$