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\left(ab+5c\right)\left(a^{2}b^{2}-5abc+25c^{2}\right)
Rewrite a^{3}b^{3}+125c^{3} as \left(ab\right)^{3}+\left(5c\right)^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).