Solve a^2x+6x=11

$$a ^ { 2 } x + 6 x = 11$$

Solve for x (complex solution)

$$x=\frac{11}{a^{2}+6}$$

$$a\neq -\sqrt{6}i\text{ and }a\neq \sqrt{6}i$$

Steps for Solving Linear Equation

Combine all terms containing x.

$$\left(a^{2}+6\right)x=11$$

Divide both sides by a^{2}+6.

$$\frac{\left(a^{2}+6\right)x}{a^{2}+6}=\frac{11}{a^{2}+6}$$

Dividing by a^{2}+6 undoes the multiplication by a^{2}+6.

$$x=\frac{11}{a^{2}+6}$$

Solve for x

$$x=\frac{11}{a^{2}+6}$$

Steps for Solving Linear Equation

Combine all terms containing x.

$$\left(a^{2}+6\right)x=11$$

Divide both sides by a^{2}+6.

$$\frac{\left(a^{2}+6\right)x}{a^{2}+6}=\frac{11}{a^{2}+6}$$

Dividing by a^{2}+6 undoes the multiplication by a^{2}+6.

$$x=\frac{11}{a^{2}+6}$$

Solve for a (complex solution)

$$a=-\sqrt{-6+\frac{11}{x}}$$

$$a=\sqrt{-6+\frac{11}{x}}\text{, }x\neq 0$$

Solve for a

$$a=\sqrt{-6+\frac{11}{x}}$$

$$a=-\sqrt{-6+\frac{11}{x}}\text{, }x>0\text{ and }x\leq \frac{11}{6}$$