Solve a^{2}=2ab-(b^2*a^2)+3a+a^2b^2=

$$a ^ { 2 } = 2 a b - ( b ^ { 2 } \cdot a ^ { 2 } ) + 3 a + a ^ { 2 } b ^ { 2 } =$$

Solve for b (complex solution)

$$\left\{\begin{matrix}\\b=\frac{a-3}{2}\text{, }&\text{unconditionally}\\b\in \mathrm{C}\text{, }&a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$2ab-b^{2}a^{2}+3a+a^{2}b^{2}=a^{2}$$

Combine -b^{2}a^{2} and a^{2}b^{2} to get 0.

$$2ab+3a=a^{2}$$

Subtract 3a from both sides.

$$2ab=a^{2}-3a$$

Divide both sides by 2a.

$$\frac{2ab}{2a}=\frac{a\left(a-3\right)}{2a}$$

Dividing by 2a undoes the multiplication by 2a.

$$b=\frac{a\left(a-3\right)}{2a}$$

Divide a\left(-3+a\right) by 2a.

$$b=\frac{a-3}{2}$$

Solve for b

$$\left\{\begin{matrix}\\b=\frac{a-3}{2}\text{, }&\text{unconditionally}\\b\in \mathrm{R}\text{, }&a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$2ab-b^{2}a^{2}+3a+a^{2}b^{2}=a^{2}$$

Combine -b^{2}a^{2} and a^{2}b^{2} to get 0.

$$2ab+3a=a^{2}$$

Subtract 3a from both sides.

$$2ab=a^{2}-3a$$

Divide both sides by 2a.

$$\frac{2ab}{2a}=\frac{a\left(a-3\right)}{2a}$$

Dividing by 2a undoes the multiplication by 2a.

$$b=\frac{a\left(a-3\right)}{2a}$$

Divide a\left(-3+a\right) by 2a.

$$b=\frac{a-3}{2}$$

Solve for a

$$a=2b+3$$

$$a=0$$