Solve a^2+n-12=(0)

$$a ^ { 2 } + n - 12 = ( 0 )$$

Solve for n

$$n=12-a^{2}$$

Solution Steps

Subtract a^{2} from both sides. Anything subtracted from zero gives its negation.

$$n-12=-a^{2}$$

Add 12 to both sides.

$$n=-a^{2}+12$$

Solve for a (complex solution)

$$a=-\sqrt{12-n}$$

$$a=\sqrt{12-n}$$

Solve for a

$$a=\sqrt{12-n}$$

$$a=-\sqrt{12-n}\text{, }n\leq 12$$