Solve a+c=4ac

$$a + c = 4 a c$$

Solve for a

$$a=-\frac{c}{1-4c}$$

$$c\neq \frac{1}{4}$$

Steps for Solving Linear Equation

Subtract 4ac from both sides.

$$a+c-4ac=0$$

Subtract c from both sides. Anything subtracted from zero gives its negation.

$$a-4ac=-c$$

Combine all terms containing a.

$$\left(1-4c\right)a=-c$$

Divide both sides by 1-4c.

$$\frac{\left(1-4c\right)a}{1-4c}=-\frac{c}{1-4c}$$

Dividing by 1-4c undoes the multiplication by 1-4c.

$$a=-\frac{c}{1-4c}$$

Solve for c

$$c=-\frac{a}{1-4a}$$

$$a\neq \frac{1}{4}$$

Steps for Solving Linear Equation

Subtract 4ac from both sides.

$$a+c-4ac=0$$

Subtract a from both sides. Anything subtracted from zero gives its negation.

$$c-4ac=-a$$

Combine all terms containing c.

$$\left(1-4a\right)c=-a$$

Divide both sides by 1-4a.

$$\frac{\left(1-4a\right)c}{1-4a}=-\frac{a}{1-4a}$$

Dividing by 1-4a undoes the multiplication by 1-4a.

$$c=-\frac{a}{1-4a}$$