Solve for b
b=-\frac{\sqrt{3}\left(a+\sqrt{3}-2\right)}{3}
Solve for a
a=-\sqrt{3}b+2-\sqrt{3}
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b\sqrt{3}=2-\sqrt{3}-a
Subtract a from both sides.
\sqrt{3}b=-a+2-\sqrt{3}
The equation is in standard form.
\frac{\sqrt{3}b}{\sqrt{3}}=\frac{-a+2-\sqrt{3}}{\sqrt{3}}
Divide both sides by \sqrt{3}.
b=\frac{-a+2-\sqrt{3}}{\sqrt{3}}
Dividing by \sqrt{3} undoes the multiplication by \sqrt{3}.
b=\frac{\sqrt{3}\left(-a+2-\sqrt{3}\right)}{3}
Divide 2-\sqrt{3}-a by \sqrt{3}.
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