Solve a+b=a*b-3

$$a + b = a \times b - 3$$

Solve for a

$$a=-\frac{b+3}{1-b}$$

$$b\neq 1$$

Steps for Solving Linear Equation

Subtract ab from both sides.

$$a+b-ab=-3$$

Subtract b from both sides.

$$a-ab=-3-b$$

Combine all terms containing a.

$$\left(1-b\right)a=-3-b$$

The equation is in standard form.

$$\left(1-b\right)a=-b-3$$

Divide both sides by -b+1.

$$\frac{\left(1-b\right)a}{1-b}=\frac{-b-3}{1-b}$$

Dividing by -b+1 undoes the multiplication by -b+1.

$$a=\frac{-b-3}{1-b}$$

Divide -3-b by -b+1.

$$a=-\frac{b+3}{1-b}$$

Solve for b

$$b=-\frac{a+3}{1-a}$$

$$a\neq 1$$

Steps for Solving Linear Equation

Subtract ab from both sides.

$$a+b-ab=-3$$

Subtract a from both sides.

$$b-ab=-3-a$$

Combine all terms containing b.

$$\left(1-a\right)b=-3-a$$

The equation is in standard form.

$$\left(1-a\right)b=-a-3$$

Divide both sides by 1-a.

$$\frac{\left(1-a\right)b}{1-a}=\frac{-a-3}{1-a}$$

Dividing by 1-a undoes the multiplication by 1-a.

$$b=\frac{-a-3}{1-a}$$

Divide -3-a by 1-a.

$$b=-\frac{a+3}{1-a}$$