Solve for p (complex solution)
\left\{\begin{matrix}p=\frac{x+Z}{2q}\text{, }&q\neq 0\\p\in \mathrm{C}\text{, }&Z=-x\text{ and }q=0\end{matrix}\right.
Solve for p
\left\{\begin{matrix}p=\frac{x+Z}{2q}\text{, }&q\neq 0\\p\in \mathrm{R}\text{, }&Z=-x\text{ and }q=0\end{matrix}\right.
Solve for Z
Z=-\left(x-2pq\right)
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2pq-x=Z
Swap sides so that all variable terms are on the left hand side.
2pq=Z+x
Add x to both sides.
2qp=x+Z
The equation is in standard form.
\frac{2qp}{2q}=\frac{x+Z}{2q}
Divide both sides by 2q.
p=\frac{x+Z}{2q}
Dividing by 2q undoes the multiplication by 2q.
2pq-x=Z
Swap sides so that all variable terms are on the left hand side.
2pq=Z+x
Add x to both sides.
2qp=x+Z
The equation is in standard form.
\frac{2qp}{2q}=\frac{x+Z}{2q}
Divide both sides by 2q.
p=\frac{x+Z}{2q}
Dividing by 2q undoes the multiplication by 2q.
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