Solve Y=2(x+3)^2-4,quadx=-5 | Microsoft Math Solver

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Y=2\left(-5+3\right)^{2}-4

Consider the first equation. Insert the known values of variables into the equation.

Y=2\left(-2\right)^{2}-4

Add -5 and 3 to get -2.

Y=2\times 4-4

Calculate -2 to the power of 2 and get 4.

Y=8-4

Multiply 2 and 4 to get 8.

Y=4

Subtract 4 from 8 to get 4.

Y=4 x=-5

The system is now solved.

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