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Y=0.09\left(x^{3}-150x^{2}+7500x-125000\right)+15
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-50\right)^{3}.
Y=0.09x^{3}-13.5x^{2}+675x-11250+15
Use the distributive property to multiply 0.09 by x^{3}-150x^{2}+7500x-125000.
Y=0.09x^{3}-13.5x^{2}+675x-11235
Add -11250 and 15 to get -11235.