Solve for A
\left\{\begin{matrix}A=\frac{B}{X}+5\text{, }&X\neq 0\\A\in \mathrm{R}\text{, }&X=0\text{ and }B=0\end{matrix}\right.
Solve for B
B=X\left(A-5\right)
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XA=B+5X
Add 5X to both sides.
\frac{XA}{X}=\frac{B+5X}{X}
Divide both sides by X.
A=\frac{B+5X}{X}
Dividing by X undoes the multiplication by X.
A=\frac{B}{X}+5
Divide B+5X by X.
B=XA-5X
Swap sides so that all variable terms are on the left hand side.
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